Question

Find the smallest number which when divided by 10 and 15 , leaves a remainder of 5

Answer 1

Answer:

35

Step-by-step explanation:

Smallest number divisible by any two numbers = HCF of those numbers.

So,

HCF of 10 & 15 is,

10 = 5 x 2

15 = 5 x 3, means, HCF = 30.

Hence, 30 is the smallest number which is divisible by both 15 and 10.

But we need a number which leaves a remainder of 5.

So, required number = 30 + 5 = 35

Answer 2

Answer:

35

Step-by-step explanation:

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