Find the smallest number which when divided by 111,222,333 leaves remainder 4 in each case
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Answer:
24 = 2³ × 3
36 = 2² × 3²
64 = 2^6
LCM = product of prime factors with highest power
☛ LCM = 2^6 × 3²
☛ LCM = 64 × 9
☛ LCM = 576
Required number which when divided by these numbers gives remainder 4 in each case :
===> LCM - 4
===> 576 - 4
===> 572
Hence, the required number is 572
Step-by-step explanation:
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