Math, asked by kumardhana7619, 1 month ago

find the smallest number which when divided by 112,140 and 168 leaves the remainder 8 in each case

Answers

Answered by Luckydancer950
1

Answer:

Thus, looking at the factors, Viz. 28, 4, 5 and 6, we can determine that the LCM of 112, 140 and 168 would be 28*60 = 1680.

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