Math, asked by renusantuka, 9 months ago

Find the smallest number which when divided by 12, 15, 18, 24, 36 leaves no remainder

Answers

Answered by krishnmnaik

6

Answer:

the number is 360.

Step-by-step explanation:

LCM of the given numbers

12=2*2*3

15=3*5

18=2*3*3

24=2*2*2*3

36=2*2*3*3

LCM=2*2*2*3*3*5

=360

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