Math, asked by maliksbgee01, 9 months ago

Find the smallest number which when divided by 12 15 18 and 27 leaves as remainder 8 11 14 and 23 respectively

Answers

Answered by jhunsahu
1

Answer: The smallest number which when divided by 12,15,18 and 27 leaves as remainder 8,11,14, and 23 respectively is 536. Answer: The answer is 4.

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