Find the smallest number which when divided by 12, 15, 18 and 27 leaves as
remainder 8, 11, 14 and 23 respectively.
Answers
Answered by
0
Answer:
the right answer is 539
Answered by
0
Answer:
544 is the answer
Step-by-step explanation:
LCM(12,15,18,27) + 4
540+4
544
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