Find the smallest number which when divided by 12, 15 and 18 and leaves a remainder of 2 in each case.
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Answer:
12 is the answer of this question
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the smallest required number that leaves the remainder 2 when divided by 12, 15 and 18= 360
Step-by-step explanation:
The least number which is exactly divisible by each given number is their L.C.M.
Required number L.C.M. of 12, 15, 18, 24, and 36.
∴Least required number
=2×2×3×3×5×2=360
Hence, the Answer is 360
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