Question

`Find the smallest number which when divided by 12, 15 and 18 leaves 10, 13 and16 as remainders respectively.`​

Answer 1

Answer:

538

Step-by-step explanation:

Prime factorizations first.

12 = 2 x 2 x 3

15 = 3 x 5

18 = 2 x 3 x 3

 

LCM = 2 x 2 x 3 x 3 x 3 x 5 = 540

Since all of the remainders are 2 less than the divisors, the number will be 540 - 2 = 538

Answer 2

Answer:

178

Step-by-step explanation:

Lcm of 12, 15, 18 = 180

Now 12-10 = 2 ; 15-13 = 2; 18-16 = 2

hence,

ans = 180 - (2)

      = 180 - 2

      = 178

so when you divide 178 by 12 then remainder is 10.. and when you divide 178 by 15 then remainded is 13 so on.

Thank you.