Question

Find the smallest number which when divided by 12,16,24 and 36 leaves a remainder 7 in each case

Answer 1

Answer:

Your answer is 22185

Step-by-step explanation:

First subtract 7 from 12,16,24 and 36

12-7=5

16-7=9

24-7=17

36-7=29

Now find the LCM of 5,9,17,29

all are prime numbers so the answer is

multiply:-

5×9×17×29

=22185

HOPE IT HELPS