Find the smallest number which when divided by 12 16 24 and 36 leaves a remainder 5 in each case
Answers
Answered by
1
Step-by-step explanation:
LCM of 12,16,24 and 36=144
it should leave a remainder 5. so we will add 5 to that LCM(144).
144+5=149
so the smallest no is 149 which when....5 in each case
Similar questions