Question

find the smallest number which when divided by 12, 16, and 20 leaves no remainder​

Answer 1

Answer:

Step-by-step explanation:

Here prime factors of 12=2X2X3

Prime factors of 16=2X2X2X2

Prime factors of 20=2X2X5

Now LCM of these numbers= 2X2X3X2X2X5

=240

Therefore the smallest number which when divided 12,16 and 20 leaving remainder 0 is 240

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