Find the smallest number which when divided by 12, 20, 48 separately leaves no remainder.
Answers
Answered by
2
Answer:
4
Step-by-step explanation:
we have to find the hcf and the hcf of 12,20,48
is 4
Answered by
5
Answer:
LCM ( 12 , 20, 48 ) = 240
Step-by-step explanation:
Find the smallest number which when divided by 12, 20, 48 separately leaves no remainder.
Which means 12, 20, 48 are the divisors. We need to find the dividend.
Dividend can be found by finding the
LCM ( 12 , 20, 48 )
Taking common factors out,
2 ÷ ( 12 , 20, 48 )
2 ÷ ( 6, 10, 24 )
3 ÷ ( 3, 5, 12 )
( 1, 5, 4 )
4 = 2 × 2
So the LCM = 2 × 2 × 3 × 5 × 2 × 2
= 240
Similar questions