Math, asked by dimplechopra17, 8 months ago

Find the smallest number which when divided by 12, 20, 48 separately leaves no remainder.​

Answers

Answered by Dakshvashishth
2

Answer:

4

Step-by-step explanation:

we have to find the hcf and the hcf of 12,20,48

is 4

Answered by Anonymous
5

Answer:

LCM ( 12 , 20, 48 ) = 240

Step-by-step explanation:

Find the smallest number which when divided by 12, 20, 48 separately leaves no remainder.

Which means 12, 20, 48 are the divisors. We need to find the dividend.

Dividend can be found by finding the

LCM ( 12 , 20, 48 )

Taking common factors out,

2 ÷ ( 12 , 20, 48 )

2 ÷ ( 6, 10, 24 )

3 ÷ ( 3, 5, 12 )

( 1, 5, 4 )

4 = 2 × 2

So the LCM = 2 × 2 × 3 × 5 × 2 × 2

= 240

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