Question

find the smallest number which when divided by 12 and 18 leaves a remainder 9 in each case​

Answer 1

Answer:

12= 2 x 2 x 3

18= 2 x 3 x 3.

So LCM of 12, 18 =2 x 3 x 2 x 3= 36.

Therefore 36 + 9= 45, is the smallest number, when divided by 12 or 18 will give a remainder of 9.