find the smallest number which when divided by 14, 28 and 56 leaves no remainder
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Answered by
6
Answer:
answer is 2
Step-by-step explanation:
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Answered by
8
Answer:
21 = 3x7
14 = 2x7
LCM = 2x3x7 = 42.
The smallest number is 42 which when divided by 14 and 21 leaves no remainder.
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