Math, asked by akshayshenoy9707, 11 months ago

Find the smallest number, which when divided by 14, 49 and 63 leaves a remainder of 1 in each case

Answers

Answered by SmartParjapati
20

Answer:

883

Step-by-step explanation:

LCM=882 IT'S the smallest no. Which completely decided by all these three no.

Then when we add 1 we got our ans

Which gives one remainder by deciding these no.

Answered by proguypro2348
13

Answer:

883

Step-by-step explanation:

first we have to find the lcm of 49,14 and 63.the lcm is 882.now add the remainder to the lcm=882+1=883

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