Question

Find the smallest number which when divided by 15,20,25 and 30 leaves 5 as remainder in each case ​

Answer 1

Answer:

Answer. 425 is the correct answer as L.C.M. of 15,20 ad 35 is 420.

Explanation:

Answer 2

Answer:

☞ Your Answer is 35

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$\mathtt{{\colorbox{silver}{GIVEN~~~}}}$

✭ When 15,20,25,30 is divided by a number the remainder is 5

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$\mathtt{{\colorbox{silver}{TO FIND~~~}}}$

◈ The Number?

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$\mathtt{{\colorbox{silver}{STEPS~~~}}}$

So here first we have to take the LCM of 15,20,25,30

HCF(15,20,26)

➝ 15 = 5×3

➝ 20 = 2×2×5 = 2²×5

➝ 25 = 5×5 = 5²

➝ 30 = 5×2×3

So the HCF is the product of the least power of the common factors,that is here,

➢ HCF(15,2926) = 2×5×3

➢ $\mathtt{{\colorbox{silver}{HCF = 30~~~}}}$

So now if we need a reminder 5 we have to add 5 to the HCF,that is 30+5 = 35

Verification

$➳ \frac{35}{15} = 5$

$➳ \frac{35}{20} = 5$

$➳ \frac{35}{25} = 5$

$➳ \frac{35}{30} = 5$

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