Math, asked by jaynasanger, 5 hours ago

Find the smallest number which when divided by 15 20 and 48 will in each case leaves 7 as the remainder

Answers

Answered by meghjaiswal29

2

Answer:

249

Step-by-step explanation:

LCM(15,20,48)

=240

since remainder is 9 so adding 9 to 240

9+240=249

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