Find the smallest number which when divided by 15, 20 and 48 will in each case leaves 7 as the remainder.
Answers
Answered by
0
The answer is 249.
Explanation
LCM(15,20,48)
=240
since remainder is 9 so adding 9 to 240
9+240=249.
Answered by
2
Answer:
the answer is 249 respectively
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