Find the smallest number which when divided by 15, 25 and 35 leaves a remainder 5 in each case
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Answered by
14
Answer:
The Brainliest Answer! 425 is the correct answer as L.C.M. of 15,20 ad 35 is 420. So required no. =420+5=425.
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Answered by
5
Answer:
420+5=425
Step-by-step explanation:
Find the smallest number which when divided by 15, 25 and 35 leaves a remainder 5 in each case
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