find the smallest number which when divided by 15,25 and 35 leaves a reminder 5 each case
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Step-by-step explanation:
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Answer:
The smallest no is 530.
Step-by-step explanation:
The LCM of the numbers 15, 25 and 35 will be 75∗7=525
The number has a remainder 5 when divided by 15,25,35 .In each case we are 5 short of getting a zero remainder.
So the desired number is 525+5=530
Hope this answer helps you out.
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