Math, asked by avadesh123789, 7 months ago

find the smallest number which when divided by 15,25 and 35 leaves a reminder 5 each case​

Answers

Answered by khushiyt
0

Answer:

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Step-by-step explanation:

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Answered by Anonymous
0

Answer:

The smallest no is 530.

Step-by-step explanation:

The LCM of the numbers 15, 25 and 35 will be 75∗7=525

The number has a remainder 5 when divided by 15,25,35 .In each case we are 5 short of getting a zero remainder.

So the desired number is 525+5=530

Hope this answer helps you out.

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