Question

Find the smallest number which when divided by 15 leaves remainder 5,when divided by 25 leaves remainder15 and when divided by 35 leaves remainder 25​

Answer 1

The LCM of the numbers 15, 25 and 35 will be 75∗7=525
Now, number has a remainder of 25 when divided by 35. Similarly, number has remainder 15 on dividing by 25 and remainder is 5 when divided by 15. In each case, we are 10 short of getting a zero remainder. So the desired number must be 525−10=515
Option A

Answer 2

Answer:

Option A

Step-by-step explanation:

The LCM of the numbers 15, 25 and 35 will be 75∗7=525

Now, number has a remainder of 25 when divided by 35. Similarly, number has remainder 15 on dividing by 25 and remainder is 5 when divided by 15. In each case, we are 10 short of getting a zero remainder. So the desired number must be 525−10=515.