Math, asked by sabitabharati675, 5 hours ago

Find the smallest number which when divided by 16,18 and 32 leaves a remainder of 5 in each case.

Answers

Answered by tg72866

2

Answer:

30+ 478+_478;""3680:___

Answered by parivarnalla

2

Answer:

293

Step-by-step explanation:

LCM of 16,18 & 32 =288

Hence required number is 288+5 = 293

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