Question

find the smallest number which when divided by 16, 24 and 40 leaves remainder 5 in each case.​

Answer 1

Answer:

lcm of 16,24 and 40 is

240

reminder 5 in each case so

240+5 =245 is the smallest no.

Answer 2

Answer:

hey answer is 245 because

we are doing a LCM

2 l 16,24,40

2 l 8,12,20

2 l 4,6,10

2 l 2,3,5

3 l 1,3,5

5l 1 1 5

1 1 5

LCM OF 16,24,40 =2×2×2×2×3×5 =240

HERE 240 IS THE LEAST NUMBER EXACTLY DIVISIBLE BY 16,24,40

TO GET A REMINDER 5 THE LEAST NUMBER WILL BE 240+5 =245

HENCE THE REQIRED NUMBER IS 245

THANK YOU !