Math, asked by UsarshiDas9433, 26 days ago

Find the smallest number which,when divided by 16,28,and 36 leaves no remainder

Answers

Answered by jiyarumao

2

Answer:

the only smallest no is 2

Answered by mufiahmotors

0

Answer:

The least number which is exactly divisible by each given number is their LCM

Required number is LCM of 12, 15, 18, 24 and 36.

LCM = least required number = 2\times2\times3\times3\times5\times2=3602×2×3×3×5×2=360

Hence, required number = 360

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