Find the smallest number which,when divided by 16,28,and 36 leaves no remainder
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Answer:
the only smallest no is 2
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The least number which is exactly divisible by each given number is their LCM
Required number is LCM of 12, 15, 18, 24 and 36.
LCM = least required number = 2\times2\times3\times3\times5\times2=3602×2×3×3×5×2=360
Hence, required number = 360
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