Question

find the smallest number which when divided by 16 28 and 40 will give 7 as the remainder in each case

Answer 1

Answer is – 693

Step-by-step explanation:

ans.. first, we have to subtract the remainder

16-7=9

28-7=21

40-7=33

Now, we will take the LCM of these three numbers i.e. (9,21,33)

LCM (9,21,33) = 693