find the smallest number which when divided by 161,207 and 184 leaves remainder 21 in each case????
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Answer:
11613
Step-by-step explanation:
Hence, The required smallest number which when divided by 161, 207 and 184, leaves a remainder of 21 in each case is 11613.
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Answer:
The required smallest number which when divided by 161, 207 and 184, leaves a remainder of 21 in each case is 11613.
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