Math, asked by javedakhtar9489, 8 months ago

Find the smallest number which when divided by 161 , 207 and 184 leaves remainder 21 in each case

Answers

Answered by ann2006
0

Answer:

11613

Step-by-step explanation:

To find the answer to this question, we first need to find the LCM of 161, 207 and 184 which is 11592. And then we simply need to add 21 to it. After doing that, we get the answer as 11613.

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