Find the smallest number which when divided by 161, 207 and 184 leaves
remainder 21 in each case
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Answer:
the number is 11613
Step-by-step explanation:
to get number which when divided by 161 , 207 , 184
leaves remainder 21 in each case
We need to find LCM of 161,207,184 and then add 21
that is LCM of 161,207,184 = 11592
therefore the number is 11592+21= 11613
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