find the smallest number which when divided by 18,12,24 leaves a remainder of 16,10 and 22 respectively
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0
Answer:
nR ni bhi dr bhi DNND ji de de dNnDbD dresses
Answered by
0
Answer:
70
Step-by-step explanation:
If n is any integer that leaves a remainder 16, 10, 22 when divided by 18, 12, 24 respectively, then n+2 is a common multiple of 18, 12, 24. This is the same as saying n+2 is a multiple of lcm(12,18,24)=72
The least positive integer with this property is n=70
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