Question

Find the smallest number which when divided by 18,27 and 36leaves the remainder 5 in each case

Answer 1

Answer:

113

Step-by-step explanation:

First Step : Find the LCM of 18, 27 and 36 : [18,27,36] = 108

Second Step : Add 108 by 5 : 113

## The smallest number which when divided by 18,27 and 36 leaves the remainder 5 in each case would be 113