Find the smallest number which when divided by 2,3,4,5and 6 leaves the reminder 2 in every case
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Step-by-step explanation:
The least common multiple of 2, 3, 4, 5, 6 is their LCM=60.
So, the answer is the least number such that it is a multiple of 7 and a multiple of 60 leaving remainder 1.
∴The required answer is 301.
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answer: the required number is 301. step-by-step explanation: we have to find a number that is divisible by 2, 3, 4, 5, and 6 (meaning that it is a multiple of those numbers) and that number + 1 being divisible by 7.
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