Math, asked by ajadon309, 6 months ago

Find the smallest number which when divided by 2, 4, 6, 8 and 12 leave 5 as remainder
in each case.

Answers

Answered by ajaysingh657665

0

Answer:

1 is correct answer

Step-by-step explanation:

but but I cannot be sure

Answered by anshraj20079876

0

Answer:

29

Step-by-step explanation:

LCM of 2,4,6,8 and 12 = 24

Remainder =5

Required no. =24 + 5

=29

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