Question

Find the smallest number which when divided by 20, 25 and 40 leaves a remainder 5 in each case.

Answer 1

Therefore, the smallest number which when divided by 20, 25, 35 and 40 and leaves a remainder of 14, 19, 29 and 34 respectively is 1394

Answer 2

Answer:

$20 = 4 \\ 4 \div 20 = 5 \\ \\ 25 = 5 \\ 5 \div 25 = 5 \\ \\ 40 = 8 \\ 8 \div 40 = 5$

Step-by-step explanation:

Hope you understand