Question

find the smallest number which when divided by 22,33 and 44 leaves 56 as remainder

Answer 1

Answer:

FIND LCM of 22, 33 and 44

22 = 2 X 11

33 = 3 x 11

44 = 2 x 2 x 11

so LCM is = 2 x 2 x 3 x 11 = 12 x 11 = 132

so 132 is smallest number that is divisible by 22, 33 and 44.

now whatever remainder is left you can add here in 132.

but point be noted remainder must be less then smaller number , here smaller number is 22.

you had asked that remainder should be 56. if we divide any number by 22. then how remainder can be 56.

so i thing you write a wrong number here . please correct the question and your answer is here = 132 + ( remainder )

thank you

Step-by-step explanation:

Answer 2

Answer:

132 is correct answer

Step-by-step explanation:

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