Question

find the smallest number which when divided by 24,28and 35 leaves a remainder 3 in each case



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Answer 1

24 - 3 = 21

28 - 3 = 25

35 - 3 = 32

H.C.F (21,25,32):-

21 = 3 × 7

25 = 5 × 5

32 = 2 × 2 × 2 × 2 × 2

Therefore, H.C.F (21,25,32):- 1.