find the smallest number which when divided by 24,32,40,48leaves 3 as remainder
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First let us factorize the numbers in question:
24 = 2x2x2x3
32 = 2x2x2x2x2
40 = 2x2x2x5
48 = 2x2x2x2x3
The LCM is 2x2x2x2x2x3x5 = 480.
Add 3 to 480 to get 483 which is the answer.
Check: 483/24 = 20 as quotient and 3 as remainder.
483/32 = 15 as quotient and 3 as remainder.
483/40 = 12 as quotient and 3 as remainder.
483/48 = 10 as quotient and 3 as remainder.
Answer is 483.
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