Question

Find the smallest number which when divided by 24 , 32 and 48 leaves a remainder 4 in each case.​

Answer 1

Step-by-step explanation:

the smallest number which is divided by (24-4) ,(32 - 4) , (48 - 4) exactly.

the required number = LCM of 20 , 28 , 44 is 1540

Answer 2

Answer:

100

Step-by-step explanation:

first L.C.M. of 24, 32, 48

L.C.M is 96.

smallest number is 96+4=100.