Math, asked by parmveersingh19367, 8 months ago

find the smallest number which when divided by 24, 36, and 54 gives a remainder of 5 each
a
time. (Hint: Required number (LCM of 24, 36, 54) + 51
22 22
Facts about HCF and LCM​

Answers

Answered by vthanvi
1

Step-by-step explanation:

To find the smallest number which when divided by 24,36and 54 gives the remainder 5,

We have to find the LCM of 24,36,54 and then add 5 to it.

We know that the LCM of 24, 36,54 is 216.

Therefore, the number required is 216+5=221

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