Math, asked by monusaparihar1, 2 months ago

Find the smallest number which when divided by 24 36 and 64 leaving as remainder in each case.

Answers

Answered by alexwainaina678
1

Answer:

4 \div 24 = 6 \\ 4 \div 36 = 9 \\ 4  \div 64 = 16

Answered by sukumarsawant1510
4

Step-by-step explanation:

if you just want reminder you can take any no. like 1.1, etc

but when you want specific reminder like 4 :-

when you want specific reminder like 4 :- take LCM of all and add the req reminder

for eg :-

THE LCM OF 24,36,64 IS 576

so it is completely divisible by 576

when we add 576+4= 580 the remainder of all the divisors will be 4

thus the ans if asked for 4 as reminder is 580

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