Find the smallest number which when divided by 24, 40 and 25 leaves a remainder of 10 in each case
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Step-by-step explanation:
LCM is the least no. /Smallest no. Which is divisible by all the given numbers. So, LCM of 24= 2× 2×2×3, 18= 2×3×3, 40= 2×2×2×5, 60=2×2×3×5, is all factors with greatest power, so LCM = 2^3 ×3^2 ×5^1= 8×9× 5 = 360. So , no. Leaves remainder 8 in each case is 360+8 = 368.
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