Question

Find the smallest number which when divided by 24 and 36 leaves a remainder of 5 in each case

please answer now it's correct question ​

Answer 1

Step-by-step explanation:

Claearly, we must find the greatest number which divides (24-5) and (36-5) exactly

So, the required number = HCF of 19 and 31

= 1

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Answer 2

Answer:

thanks bro if you need any help please let me know.......