Question

Find the smallest number which when divided by 25, 40, 60 leaves remainder 9 in each case.

Answer 1

Answer: 609

Step-by-step explanation:

First, we will find the LCM of 25, 40 and 60= 600

given it leaves a remainder of 9

So the number is 600+9=609.

therefore 609 is the smallest no. which when divided by 25,50 and 60 leaves a remainder of 9.