Question

Find the smallest number which when divided by
25, 40 and 60 leaves a remainder 7 in each case​

Answer 1

Which is the least number which when divided by 15, 21, and 18 leaves 7 as the remainder? Well if I'm understanding the question correctly, then the answer is quite simple. The smallest number divisible by 25, 40 and 60 is 600.

Answer 2

$\bold\red{Answer =>}$

$Here\: 25 = 5×5=5^2$

$40 = 2×2×2×5=2^3×5$

$60 = 2×2×3×5=2^2×3×5$

Therefore LCM of $25,40,60$ is

$= 2^3×3×5^2$

$= 8×3×25$

$= 600$