find the smallest number which when divided by 25 40 and 60 leaves a remainder 8
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Answer:
LCM of 25, 40 & 60 = 2*2*2*5*5*3 = 8*25*3 = 200*3 = 600. 600 perfectly divides the 3 numbers and leaves the remainder as 0. So, 600+8 = 608 is the smallest number which leaves remainder 8 when divided by 20, 40 & 60.
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Answer:
608 is the smallest no. which when divided by 25,40,and 60 leaves remainder 8.
Step-by-step explanation:
The LCM of 25 , 40 and 60 is 600
Therefore; 600 + 8 = 608 ;ans
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