Find the smallest number which when divided by 25, 40 and 60 leaves remainder 7 in each case.
Answers
Answered by
17
Hey friend, here is your answer ☺ __________________________
If we subtract the remainders from the given numbers, we get the perfect numbers which are totally divisible.
25 - 7 = 18
40 - 7 = 33
60 - 7 = 53
Now , to find the smallest number, we have to find LCM (Least Common Factor). To find LCM, we have to find the factors of these numbers.
18 = 2 × 3 × 3
33 = 3 × 11
53 = 53 (as 53 is a prime number)
Now, LCM = 3 × 3 × 11 × 2 × 53 = 7544.
The smallest number is 10494.
If we subtract the remainders from the given numbers, we get the perfect numbers which are totally divisible.
25 - 7 = 18
40 - 7 = 33
60 - 7 = 53
Now , to find the smallest number, we have to find LCM (Least Common Factor). To find LCM, we have to find the factors of these numbers.
18 = 2 × 3 × 3
33 = 3 × 11
53 = 53 (as 53 is a prime number)
Now, LCM = 3 × 3 × 11 × 2 × 53 = 7544.
The smallest number is 10494.
Similar questions