Math, asked by meenakshichaudhary40, 5 hours ago

find the smallest number which when divided by 25 40 and 60 leaves remainder 8 in each case​

Answers

Answered by something63
3

Answer:

608

Step-by-step explanation:

to get the smallest number we need to do LCM OF 25,40,60.

LCM OF 25,40&60 is 600.

the number = 600+8=608

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