Math, asked by sonalisingh7555, 8 months ago

Find the smallest number which when divided by 25,40and 48 leaves remainder 5 in each case

Answers

Answered by dunukrish

0

Step-by-step explanation:

The given numbers are 25,40,48

LCM of 25,40,48=1200.

Now 1200+5=1205

Thus the smallest number is 1205.

hope you got it.

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