Math, asked by rifatmasoodi016, 1 month ago

Find the smallest number which when divided by 25 and 30 leaves 10 as remainder.
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Answers

Answered by Anonymous
58

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\huge \rm {Question:-}

★Find the smallest number which when divided by 25 and 30 leaves 10 as remainder.

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\huge \rm {Answer:-}

 \mapsto \tt {25=5\times5}

 \mapsto \tt {30=5\times2\times3}

★Here,we can observe both common and uncommon factors.

\large \rm {\underline{Common\: factors:-}}

 \mapsto \tt {5\times5=25}

\large \rm {\underline{Common\: factors:-}}

 \mapsto \tt {5\times2\times3=30}

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\large \rm {\underline{We\: know:-}}

\small \red {\fbox{L.C.M=Common\: factors ×Uncommon\: factors}}

 \mapsto \tt {L.C.M=25×30}

\large \purple {\fbox{L.C.M=750}}

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★The smallest number which when divided by 25,30, leaves remainder 10

\large \rm {\underline{Accordingly,}}

 \mapsto \tt {750+10}

\large \pink {\fbox{760}}

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\large \rm {\underline{Thence,}}

 \implies \tt \green {The\: smallest\: number\: is\: 760}

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