Find the smallest number which when divided by 28 ,35 aand 42 gives a remainder 5 of every time please I request you please please please.
Answers
Step-by-step explanation:
1 . First start to do the LCM (LEAST COMMON
FACTOR)
2 . And, the LCM is 420
3 . Then,leaves remainder 5,means add 5 to the
Lcm of 28,35,42
Given : Number which when divided by 28 ,35 and 42 gives a remainder 5 of every time.
To Find : the smallest number
Solution:
the smallest number which when divided by 28 ,35 and 42 gives a remainder 5 of every time.
= LCM (28 , 35 , 42) + 5
LCM - Least common multiplier of given numbers is the least number which is perfectly divisible by given numbers.
LCM = product of each factor of highest power
28 = 2 * 2 * 7
35 = 5 * 7
42 = 2 * 3 * 7
LCM = 2 * 2 * 3 * 5 * 7
= 420
420 + 5 = 425
425 is the smallest number which when divided by 28 ,35 and 42 gives a remainder 5 of every time.
Learn More:
find the hcf of 75 and 243 using Euclid division algorithm express in ...
brainly.in/question/9266837
find the hcf of 96 and 336 and express it as a linear combination of ...
brainly.in/question/10749751
Find the HCF of 506 and 1155 as a linear combination of them ...
brainly.in/question/9246629