Question

Find the smallest number which when divided by 28 ,35 and 42 gives a remainder 5 of every time.​

Answer 1

Answer:

425

Step-by-step explanation:

LCM of 28, 35 and 42 is 420....and if we add 5 to 420 which is 425 then it will leave a remainder of 5 when we divide it by 28, 35 and 42

Answer 2

Given :  Number which when divided by 28 ,35 and 42 gives a remainder 5 of every time.​

To Find :   the smallest number

Solution:

the smallest number  which when divided by 28 ,35 and 42 gives a remainder 5 of every time.​

= LCM (28 , 35 , 42)  + 5

LCM  - Least common multiplier of given numbers is the least number which is perfectly divisible by given numbers.

LCM = product of each factor  of highest power

28 = 2 * 2 * 7  

35 = 5 * 7

42 = 2 *  3 * 7

LCM = 2 * 2 * 3 * 5 * 7

= 420

420 + 5 = 425

425 is  the smallest number which when divided by 28 ,35 and 42 gives a remainder 5 of every time.​

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